x^2-98x+2401=0

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Solution for x^2-98x+2401=0 equation: 



x^2-98x+2401=0

a = 1; b = -98; c = +2401;
Δ = b2-4ac
Δ = -982-4·1·2401
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{98}{2}=49$

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